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A boy of mass 36 kg moves from one end to other end of a boat of mass 72 kg on still water. If the length of the boat is 2.7 m, the displacement of the boat is

\[\begin {array} {1 1} (a)\;2.7\;m & \quad (b)\;1.35\;m \\ (c)\;5.4\;m & \quad  (d)\;0.9\;m \end {array}\]
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$\quad= \large\frac{36 \times 2.7}{72}$
$\quad= 1.35 \;m$
answered Nov 21, 2013 by meena.p

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