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Two particles of mass 2m and 3m are at a distance 'd' apart. Under their mutual gravitational force, they start moving towards each other. The acceleration of their center of mass when they are $d/2$ apart is

\[\begin {array} {1 1} (a)\;\frac{12\;Gm}{d^2} & \quad (b)\;\frac{8\;Gm}{d^2} \\ (c)\;\frac{24\;Gm}{d^2} & \quad  (d)\;zero \end {array}\]

1 Answer

The correct answer is zero
answered Nov 21, 2013 by meena.p

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