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Two blocks of masses 4 kg and 3 kg are placed on a friction less surface connected by a string. An external force gives a velocity 7 m/s to the heavier mass in the direction of the lighter , velocity of their centre of mass is

\[\begin {array} {1 1} (a)\;7m/s & \quad (b)\;3.5m/s \\ (c)\;3m/s & \quad  (d)\;4m/s \end {array}\]

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$\bar {V}_{cm}=\large\frac{m_1 \bar {V}}{m_1+m_2}$
$\qquad= 4m/s$
answered Nov 21, 2013 by meena.p
edited Jun 16, 2014 by lmohan717
 

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