\[\begin {array} {1 1} (a)\;30\;m & \quad (b)\;60\;m \\ (c)\;90\;m & \quad (d)\;40\;m \end {array}\]

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

\[\begin {array} {1 1} (a)\;30\;m & \quad (b)\;60\;m \\ (c)\;90\;m & \quad (d)\;40\;m \end {array}\]

0 votes

Since centre of mass motion will not be affected by the explosion, it will be at a distance $R$ =range from the point of projection .

=> Total distance of the 2 nd mass from the point of projection is $\large\frac{3R}{2}$

$S= \large\frac{3}{2} \times \frac{u^2}{2g}$

$\quad= \large\frac{3}{2} \times \frac{20 \times 20}{20}$

$\quad= 30 \;m$

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...