Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A shell projected from a level ground has a range R, it does not explode. At the highest point the shell explodes into two fragments having masses in the radio 1:3 with each fragment moving horizontally immediately after the explosion. If the lighter fragment falls at a distance R from the point of projection, the distance at which the other fragment falls from the point of projection is

\[\begin {array} {1 1} (a)\;2R & \quad (b)\;\frac{5R}{3} \\ (c)\;\frac{4R}{3} & \quad  (d)\;\frac{2R}{3} \end {array}\]

Can you answer this question?

1 Answer

0 votes
$m_1 \times 2R=m_2 x$
$2R= 3 \times x$
$x= \large\frac{2R}{3}$
answered Nov 21, 2013 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App