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A shell projected from a level ground has a range R, it does not explode. At the highest point the shell explodes into two fragments having masses in the radio 1:3 with each fragment moving horizontally immediately after the explosion. If the lighter fragment falls at a distance R from the point of projection, the distance at which the other fragment falls from the point of projection is

\[\begin {array} {1 1} (a)\;2R & \quad (b)\;\frac{5R}{3} \\ (c)\;\frac{4R}{3} & \quad  (d)\;\frac{2R}{3} \end {array}\]

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$m_1 \times 2R=m_2 x$
$2R= 3 \times x$
$x= \large\frac{2R}{3}$
answered Nov 21, 2013 by meena.p

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