A man of mass 40 kg is standing on a uniform Planck of mass 60 kg lying on a horizontal friction less ice. The man walks from one end to the other end of the Planck. The distance walked by the man relative to ice is (length of Planck=5 m)

Question

\[\begin {array} {1 1} (a)\;2m & \quad (b)\;3m \\ (c)\;5m & \quad  (d)\;4m \end {array}\]

Answer 1

$d= \large\frac{mL}{m_1+m_2}$

$\quad= \large\frac{40 \times 5 m}{100}$

$\quad=2m$