Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

A particle of mass 4 m which is at rest explodes into three fragments. Two of the fragments each of mass m are found to move with speed V each in mutually perpendicular directions. The minimum energy released in the process of explosion is

\[\begin {array} {1 1} (a)\;\frac{2}{3} mv^2 & \quad (b)\;\bigg(\frac{3}{2}\bigg)mv^2 \\ (c)\;\bigg(\frac{4}{3}\bigg)mv^2 & \quad  (d)\;\bigg(\frac{3}{4}\bigg)mv^2 \end {array}\]

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...