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The momentum of a moving particle is vectorially given as $\overrightarrow{p}=p_0(\cos t \hat {i}+\sin t \hat {j}).$ Where t stands for time.

Choose the correct option: $\begin{array}{1 1} \text{(a) The applied force is constant.} \\ \text{(b) The momentum is constant.} \\ \text{(c) The applied force always remains perpendicular to momentum.} \\ \text{(d) The applied force is always parallel to the momentum.} \end{array}$
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$\overrightarrow {p}=p_o \cos t \hat i+p_o \sin t \hat j$
$\bar {F}=\large\frac{dp}{dt}$
$\quad=-p_0 \sin t \hat i+p_0 \cos t \hat j$
$\overrightarrow{F}.\overrightarrow {p}=0$
hence c is correct answer.
answered Nov 22, 2013 by meena.p
edited Jun 17, 2014 by lmohan717
 

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