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If a matrix has 28 elements, what are the possible orders it can have?
$\begin{array}{1 1}(14,2),(2,14),(4,7),(7,4) \\ (1,28),(28,1),(14,2),(2,14),(4,7)\\ (1,28),(28,1),(14,2),(2,14),(4,7),(7,4) \\ All \;the\;above \end{array} $
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asked
Dec 21, 2012
by
sreemathi.v
edited
Jun 29, 2016
by
meena.p
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1 Answer
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If a matrix is of order $m\times n $.So the elements of the matrix is $m\times n$.
Hence we have to find all possible orders of a matrix with 28 elements.
Find all possible ordered pair of natural numbers whose product is 28.
All possible ordered pairs are
$\Rightarrow$ (1,28),(28,1),(14,2),(2,14),(4,7),(7,4)
Hence the possible orders are (1,28),(28,1),(14,2),(2,14),(4,7),(7,4).
answered
Mar 21, 2013
by
sharmaaparna1
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