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A sphere of mass m moving horizontally $V_0$ collides against a pendulum bob of mass m. If the two masses stick together after the collision then the maximum height attained is

 

 

\[\begin {array} {1 1} (a)\;\frac{V_0^2}{2g} & \quad (b)\;\frac{V_0^2}{4g} \\ (c)\;\frac{V_0^2}{6g} & \quad  (d)\;\frac{V_0^2}{8g} \end {array}\]

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momentum before collision = momentum after collision
$mV_0=2mV$
$V= \large\frac{V_0}{2}$
By energy conservation
$\large\frac{1}{2}$$ (2m) \bigg (\large\frac{V_0}{2}\bigg)^2 $$=2mgh$
$h= \large\frac{V_0^2}{8g}$
answered Nov 22, 2013 by meena.p
 

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