Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A sphere of mass m moving with constant velocity $V$ collide head on with another stationary sphere of same mass. If e is the coefficient of restitution then the ratio of the final velocities of the first and second sphere is

\[\begin {array} {1 1} (a)\;\frac{1+e}{1-e} & \quad (b)\;\frac{1-e}{1+e} \\ (c)\;\frac{e}{1-e} & \quad  (d)\;\frac{1+e}{e} \end {array}\]

Can you answer this question?

1 Answer

0 votes
Let $V_1$ and $V_2$ be the velocities after collision in the same direction by momentum conservation
Applying Newton's law of restitution along the common normal :
$\large\frac{relative\;velocity\;of\;separation}{relative \;velocity \;of \;approach}$$=-e$
$\quad 2V_2=(1+e)V$
$\qquad V_2= \bigg(\large\frac{1+e}{2}\bigg)$V
$\qquad V_1= \bigg(\large\frac{1-e}{2}\bigg)$V
answered Nov 22, 2013 by meena.p
edited Jun 17, 2014 by lmohan717

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App