# A stationary body of mass 3 kg explodes into three equal pieces. Two of the pieces fly off at right angles to each other , one with velocity $2 \hat i \;m/s$ and the other with velocity $3 \hat j\; m/s$. If the explosion takes place in $10^{-5}s,$ the average force acting on the third piece in Newtons is
$\begin {array} {1 1} (a)\;(2 \hat i+ 3 \hat j) \times 10^{-5} & \quad (b)\;-(2 \hat i+ 3 \hat j) \times 10^{+5} \\ (c)\;(3 \hat i- 2 \hat j) \times 10^{5} & \quad (d)\;(2 \hat i- 3 \hat j) \times 10^{-5} \end {array}$