For a mixed doubles game 2 husbands and 2 wives are to be selected.

First of all 2 husbands can be selected in $^5C_2 $ ways.

Their respective wives are exempted in that game and

two wives are to be selected from the remaining 3 wives in $^3C_2$ ways.

Once the team is selected each team can be mixed in two ways, $i.e.,$ $H_1,W_1 $ and $H_1,W_2$

$\therefore\:$ The required ways $=^5C_2.^3C_2.2=60$.