logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XII  >>  Math  >>  Model Papers
0 votes

A man and his wife appear for an interview for two posts. The probability of husband’s selection is \( \frac{1}{7} \) and that of the wife’s selection is \( \frac{1}{5} \) . Find the probability that only one of them will be selected.

Can you answer this question?
 
 

1 Answer

+1 vote
Solution :
Let A be the event that husband is selected and B be the event that the wife is selected
then $P(A) =\large\frac{1}{7}$ and $P(B) =\large\frac{1}{5}$
$P(\bar {A}) =\bigg(1- \large\frac{1}{7} \bigg) =\large\frac{6}{7}$
$P(\bar {B}) =\bigg(1- \large\frac{1}{5} \bigg) =\large\frac{4}{5}$
Required probability is
$P(A) .P(\bar {B}) +P( \bar {A}) . P(B) $
$\qquad = \large\frac{1}{7} \times \large\frac{4}{5} +\large\frac{1}{5} \times \large\frac{6}{7}$
$\qquad= \large\frac{2}{7}$
answered Dec 5, 2016 by meena.p
 

Related questions

Ask Question
Tag:MathPhyChemBioOther
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...