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If the sum of $5^{th}\:and\:6^{th}$ terms in the expansion of $(a-b)^n$, $n\geq5$, is 0, then $\large\frac{a}{b}$ = ?

$\begin{array}{1 1} \frac{n-5}{6} \\ \frac{n-4 }{5} \\ \frac{5}{n-4} \\ \frac{6}{n-5} \end{array} $

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Given: $T_5+T_6=0$ in the expansion of $(a-b)^n$
answered Nov 24, 2013 by rvidyagovindarajan_1

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