Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A particle of mass m and velocity V collides obliquely elastically with a stationary particle of mass 'm'. The angle between the velocity vectors of the two particles after the collision is

\[\begin {array} {1 1} (a)\;45^{\circ} & \quad (b)\;30^{\circ} \\ (c)\;90^{\circ} & \quad  (d)\;None\;of\;these \end {array}\]

Can you answer this question?

1 Answer

0 votes
Collision is elastic.
Hence velocities along the line of impact will be exchanged.
Velocity of particle along line of impact $=V \cos \theta$
Velocity of particle perpendicular to line of impact
$ V \sin \theta= v \times \large\frac{1}{2}$
Velocity of disc $=\large\frac{ v \sqrt 3}{3}$
Particles will move perpendicular to disc.
The 2 bodies will move at right angles.
Hence c is the correct answer.
answered Nov 25, 2013 by meena.p
edited Apr 2, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App