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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
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A wheel rotates with a constant acceleration of $2.0\;radians /s^2$. If the wheel starts from rest, the number of revolutions it makes in the first $10$ seconds will be approximately

\[\begin {array} {1 1} (a)\;8 & \quad (b)\;16 \\ (c)\;24 & \quad  (d)\;32 \end {array}\]

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$\theta= \large\frac{1}{2} \alpha\; t^2$
$ 2\pi $(no of revolutions) $=\large\frac{1}{2} $$ \times 2 \times 100$
$n= \large\frac{50}{\pi}$


answered Nov 25, 2013 by meena.p
edited Jul 28, 2014 by thagee.vedartham

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