logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Plane

The wheel of a car is rotating at the rate of 1200 revolutions per minute. On pressing the acceleration for 10 seconds, it starts rotating at 4500 revolutions per minute. The angular acceleration of the wheel is

\[\begin {array} {1 1} (a)\;30\;rad/s^2 & \quad (b)\;1880\;deg/s^2 \\ (c)\;40\;rad/s^2 & \quad  (d)\;1980\;deg/s^2 \end {array}\]

Download clay6 mobile app

1 Answer

$w =w_0 + \alpha t $
$\alpha =\large\frac{w-w_0}{t}$
$\qquad= \large\frac{\Large\frac{4500}{60}-\Large\frac{1200}{60}}{10}$
$\qquad= \large\frac{75-20}{10}$
$\qquad=\large\frac{55}{10}$
$\qquad= 5.5\;rev/s^2$
$\qquad= 36 \times 55 = 1980 \;deg /s^2$
answered Nov 25, 2013 by meena.p
edited May 26, 2014 by lmohan717
 

Related questions

...
X