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A wheel has moment of inertia $5 \times 10^{-3} kg m^2$ and is making $20\; kw/s$ The torque needed to stop it in 10 s is

\[\begin {array} {1 1} (a)\;2 \pi \times 10^{-2} Nm & \quad (b)\;2.5 \pi \times 10^{-2} \;Nm \\ (c)\;4 \pi \times 10^{-2} Nm & \quad  (d)\;4.5 \pi \times 10^{-2} Nm \end {array}\]

1 Answer

$z= I \alpha$
$\quad= \large\frac{I(w_2-w_1)}{t}$
answered Nov 25, 2013 by meena.p
 

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