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On a uniform rod of length l and mass M, two identical masses m are kept at the extreme ends. What is the moment of inertia of the system about an axis passing through its center and perpendicular to its length ?

\[\begin {array} {1 1} (a)\;\frac{(M+6m)l^2}{12} & \quad (b)\;\frac{(M+6m)l^2}{3} \\ (c)\;\frac{Ml^2}{12}+\frac{ml^2}{6} & \quad  (d)\;\frac{Ml^2}{12}+2 ml^2 \end {array}\]

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$\large\frac{Ml^2}{12}$$+2 m(l/2))^2$
$\quad=\large\frac{Ml^2}{12}+\frac{Ml^2}{2}$
answered Nov 26, 2013 by meena.p
 

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