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# The moment of inertia of a sphere of mass M and radius R about an axis passing through centre is $\large\frac{2}{5}\;$$MR^2. The radius of gyration of the sphere about a parallel axis to the sphere is $\begin {array} {1 1} (a)\;\frac{7}{5}\;R & \quad (b)\;\frac{3}{5}\;R \\ (c)\;\sqrt {\frac{7}{5}}\;R & \quad (d)\;\sqrt {\frac{2}{5}}\;R \end {array}$ Can you answer this question? ## 1 Answer 0 votes Parallel areas theorem I= I_{cm}+Md^2 I_{AB}=\large\frac{2}{5}$$ MR^2+MR^2$
$\qquad= \large\frac{7}{5}$$MR^2$
edited Jun 18, 2014