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Three rings each of mass M and radius R are arranged as shown. The moment of inertia of the system about $YY'$ will be


\[\begin {array} {1 1} (a)\;3\;MR^2 & \quad (b)\;\frac{3}{2}\;MR^2 \\ (c)\;5\;MR^2 & \quad  (d)\;\frac{7}{2} MR^2 \end {array}\]
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$I= \large\frac{MR^2}{2}$$+2\bigg[\large\frac{3}{2}$$ MR^2\bigg]$
$\qquad= \large\frac{7}{2}$$MR^2$
answered Nov 26, 2013 by meena.p
edited Jun 18, 2014 by lmohan717

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