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The Bond angle of Ammonia

$(a)\;107^{\large\circ}\qquad(b)\;107^{\large\circ}38'\qquad(c)\;109^{\large\circ}28'\qquad(d)\;109^{\large\circ}$

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Decrease in bond angle due to repulsion between lone pairs.
Hence (a) is the correct answer.
answered Nov 26, 2013 by sreemathi.v
edited Apr 4, 2014 by archana.ghode.12_1
 
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