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The Bond angle of Ammonia

$(a)\;107^{\large\circ}\qquad(b)\;107^{\large\circ}38'\qquad(c)\;109^{\large\circ}28'\qquad(d)\;109^{\large\circ}$

Can you answer this question?

Decrease in bond angle due to repulsion between lone pairs.
Hence (a) is the correct answer.
answered Nov 26, 2013
edited Apr 4, 2014