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From a disc of mass M and radius R, a smaller disc of radius $\large\frac{R}{2}$ is cut out as shown. The moment of inertia of the remaining portion about an axis through the centre 0 and perpendicular to the plane of the disc is

\[\begin {array} {1 1} (a)\;\frac{17MR^2}{32} & \quad (b)\;\frac{13MR^2}{32} \\ (c)\;\frac{11}{32}MR^2 & \quad  (d)\;\frac{MR^2}{2} \end {array}\]

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