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How does stability of chalcogens vary

$\begin{array}{1 1}(a)\;H_2O>H_2Se>H_2Te>H_2Po>H_2S\\(b)\;H_2O>H_2S>H_2Se>H_2Te>H_2Po\\(c)\;H_2O>H_2S>H_2Se>H_2Po>H_2Te\\(d)\;H_2O>H_2Se>H_2S>H_2Po>H_2Te\end{array}$

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Owing to the decrease in (M-H) dissociation enthalpy from $H_2O$ to $H_2PO$ the stability of hydride also decreases in same order.
Hence (b) is the correct answer.
answered Nov 26, 2013 by sreemathi.v
 
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