Shape of $H_2S$ is

$\begin{array}{1 1}(a)\;Tetrahydral&(b)\;pyramidal\\(c)\;T \;shape&(d)V-bent\;shape\end{array}$

Sulphur has 6 valence electrons, of which two are involved in the formation of the two S-H bonds
This leaves two lone pairs, which prevent the bonding electrons from forming a linear configuration by crowding and repulsion
Therefore the shape is a "V", with approximately 92 degrees between the two S-H bonds.
Hence (d) is the correct answer.
edited Oct 23, 2017 by meena.p