Browse Questions

# Bond angle of $H_2O$ is

$(a)\;109^{\large\circ}\qquad(b)90^{\large\circ}\qquad(c)\;120^{\large\circ}\qquad(d)\;104^{\large\circ}30'$

Due to lp-lp and lp-bp repulsions
Hence (d) is the correct answer.