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Oxydazation states of oxygen are :

$\begin{array}{1 1}(a)\;-II,-I,+I,+II\\(b)\;-II,+I,-I,-II\\(c)\;+II,+I,+VI,+V,-I,-II\\(d)\;+II,-I,+VI,-VI,+V,-I\end{array}$

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Doesn't show higher oxidation states like +IV or VI because of absence of d-shell
Hence (a) is the correct answer.
answered Nov 27, 2013 by sreemathi.v
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