# The state of hybridization of Boron in $BCl_3$

$(a)sp^3\qquad(b)\;sp^2\qquad(c)\;sp\qquad(d)\;spd^3$

Solution :
In $BCl_3$ molecule , B atom assumes $sp^2$ hybrid orbitals are used to form sigma bond with 3 chlorine atoms to give trigonal planar structure .
edited Nov 21, 2017