Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Equilibrium
Answer
Comment
Share
Q)

If $K_1$ and $K_2$ are respective equilibrium constants of two reactions: $XeF_6 (g) + H_2O(g) \rightleftharpoons XeOF_4 (g) + 2HF(g)$ and $XeO_4 (g) + XeF_6(g) \rightleftharpoons XeOF_4 (g) + 2XeO_3F_2(g)$ Then equilibrium constant for the reaction $XeO_4(g) + 2HF(g) \rightleftharpoons XeO_3F_2(g) + H_2O(g)$ will be

(a) $K_1K_2$

(b) $\frac{K_1}{(K_2)^2}$

(c) $K_1(K_2)^{-1}$

(d) $\frac{K_2}{K_1}$

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...