BOH is a weak base. Molar concentration of BOH provides a [OH^-] of $1.5 \times 10^{-3}$ M is [Given $K_b$ (BOH) = $1.5 \times 10^{-3}$]

Question

(a) $1.5 \times 10^{-5}$ M

(b) 0.015 M

(c) 0.0015 M

(d) 0.15 M