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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Equilibrium
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Assuming 100% ionization in case of strong electrolytes which of the following will have minimum $pH$?

(a) 0.01 M $NH_4Cl$

(b) 0.01 M $(NH_4)_2SO_4$

(c) 0.01 M $(NH_4)_3PO_4$

(d) All will have same $pH$

Can you answer this question?

1 Answer

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Answer: $0.01 M (NH_4)_2SO_4$
Minimum $pH$ means maximum $[H^+]$
$NH_4Cl \longrightarrow NH_4^+ + Cl^-$
$NH^+_4 + H_2O \rightleftharpoons NH_4OH + H^+$
$\therefore [H^+] = 0.01 \times K_h$
In case of $(NH_4)_2SO_4$, $[H^+] = 0.02 \times K_h$
However $(NH_4)_3PO_4$ wil be almost neutral ($pH \approx 7$) as it is a salt of a weak acid and a weak base. Thus pH will be minimum (i.e., highest $H^+$ concentration) in case of 0.01 M $(NH_4)_2SO_4$.


answered Nov 29, 2013 by mosymeow_1

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