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Hydrolysis of chloroform with aqueous KOH gives

$\begin{array}{1 1}(a)\;COCl_2&(b)\;CH_3NC\\(c)\;HCOOK&(d)\;CH_2Cl(OH)\end{array}$

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$CHCl_3\overset{OH}{\rightarrow}CH(OH)_3{\overset{\Large\rightarrow}{-H_2O}}HCOOH \overset{K^+}{\rightarrow}HCOOK$
$HCOOK\Rightarrow $Pottassium format
Hence (c) is the correct answer.
answered Nov 28, 2013 by sreemathi.v
 
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