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$H_2B_4O+5H_2O\rightarrow x$. $x$ is

$\begin{array}{1 1}(a)\;H_3BO_3&(b)\;2H_3BO_3\\(c)\;4H_3BO_3&(d)\;H_2B_4O_3\end{array}$

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$H_2B_4O_7+5H_2O\rightarrow 4H_3BO_3$
Hence (c) is the correct answer.
answered Nov 28, 2013 by sreemathi.v
 
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