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When $B_2H_6$ reacts with $H_2O$ or alkalies and produces $x+y$ is liberated.The $y$ liberated is

$(a)\;CO_2\qquad(b)\;H_2\qquad(c)\;O_2\qquad(d)\;CO$

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The y liberated is $H_2$
Hence (b) is the correct answer.
answered Nov 28, 2013 by sreemathi.v
 
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