$(a)\;625\qquad(b)\;1250\qquad(c)\;312 \frac{1}{2}\qquad(d)\;\infty$

r=1/2

sum to infinity= a/(1-r)

=625/2(1-1/2)

=1250/2 ===625

so a is the correct one

note: however you are don't waste your time by doing this question and also don't give chance to other to waste their time by asking this type os questions answer my questions asked by nikunj jain285 if you know and want to do something in our prestigious life

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