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In a GP, given that the first term is $ 312 ½ $ and the common ratio is $ 1/2 $ find the sum of the terms of the series to infinity.

$(a)\;625\qquad(b)\;1250\qquad(c)\;312 \frac{1}{2}\qquad(d)\;\infty$

1 Answer

it is provided that first term a=625/2


sum to infinity= a/(1-r)


                      =1250/2 ===625

            so a is the correct one

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