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A gas decolourises $Br_2$ in $CCl_4$ and forms a precipitate with Ammoniacal silver nitrate .The gas is

$\begin{array}{1 1}(a)\;C_2H_2&(b)\;C_2H_4\\(c)\;C_2H_6&(d)\;CH_4\end{array}$

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1 Answer

It compound decolourises $Br_2/CCl_4$ then it must be unsaturated and if it gives a white ppt with $AgNO_3$ then surety of compound is alkyne is $HC\equiv CH$
Hence (a) is the correct answer.
answered Nov 29, 2013 by sreemathi.v
 
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