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$\Rightarrow A\overset{HBr}{\rightarrow}C_2H_5Br\overset{B}{\rightarrow}A$.A is

$\begin{array}{1 1}(a)\;C_2H_4&(b)\;C_2H_5Cl\\(c)\;C_2H_5OH&(d)\;C_2H_2\end{array}$

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According to (c)
$C_2H_5OH$ and $KOH/\Delta$
$C_2H_5OH+HBr\rightarrow C_2H_5Br\overset{\overset{KOH}{\large\rightarrow}}{\Delta}C_2H_5OH+KBr$
Hence (c) is the correct answer.
answered Nov 29, 2013 by sreemathi.v
 
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