Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A small object density rolls up a curved surface with an initial velocity V. It reaches up to a maximum height of $ \large\frac{3V^2}{4g}$ with respect to the initial position. The object is

$\begin{array}{1 1} ring \\ solid \;sphere \\ hollow\;sphere \\ disc \end{array} $

Can you answer this question?

1 Answer

0 votes
Energy conservation
$\large\frac{1}{2}$$mv^2 +\large\frac{1}{2}$$Iw^2=mgh$
$\large\frac{v^2}{2g} \bigg[ 1+ \large\frac{k^2}{r^2}\bigg]$$=h$
$h= \large\frac{3v^2}{4g}$


answered Dec 5, 2013 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App