Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A small spherical ball is released from a point at a height h on a rough track. Assuming that it does not slip any where , find its linear speed when it rolls on the horizontal part of the track.

\[\begin {array} {1 1} (a)\;\sqrt {\frac{11\;gh}{7}} & \quad (b)\;\sqrt{\frac{3gh}{5}} \\ (c)\;\sqrt {\frac{7gh}{5}} & \quad  (d)\;\sqrt {\frac{10gh}{7}} \end {array}\]

Can you answer this question?

1 Answer

0 votes
$\large\frac{1}{2}mv^2 \bigg[ 1+ \large\frac{k^2}{r^2}\bigg]$$=mgh$
$v^2 [1+ \large\frac{2}{3} \bigg]$$ =gh$
$=> v= \sqrt {\large\frac{3}{5} gh}$
answered Dec 5, 2013 by meena.p
edited Jun 24, 2014 by lmohan717

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App