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Home  >>  CBSE XII  >>  Math  >>  Model Papers
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: If the given lines \( \frac{x-1}{-3} = \frac{y-2}{2k} = \frac{z-3}{2} \) and \( \frac{x-1}{3k} = \frac{y-1}{1} = \frac{z-6}{-5} \) are perpendicular, then k is \[ \begin{array} (A)\: -10 \quad & (B) \: \frac{10}{7} \\ (C)\: \frac{-10}{7} \quad & (D)\: \frac{-7}{10} \end{array} \]

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