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Refer to the below equation :


The products are

$\begin{array}{1 1}a)\;constitutional \;isomers\\b)\;diastereomers\\c)\;enantiomers\\d)\;Geometrical \;isomers\end{array}$

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The addition to double bond can take place in two ways one above the plane and another below the plane so that a mixture of diastereomers results are of
Hence (b) is the correct answer.
answered Dec 5, 2013 by sreemathi.v
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