Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Reaction of 1 molr of each $Br_2$ and phco$CH_2CH_3$ in basic solution yields 0.5 moles of ph$COCBr_2CH_3$ And 0.5 moles of unreacted ph$COCH_2CH_3$. It suggests:

$\begin{array}{1 1}a)\; Bromintion\; decreases\; the\; furthure\; rate \;of\; bromination\\b)\; Bromination\; increases\; the\; further\; rate\; of \;bromination\\c) \;Bromintion\; decreases\; the\; rate\; of\; tautomerization\\d) \; Bromination \;increases \;the\; reactivity\; of\; carbonyl\; carbon\; due\; to\; its\; bigger\; size\end{array}$

Can you answer this question?

1 Answer

0 votes
on initial bromination we get ph$COCBr_2CH_3$ which naturally decreases further bromination due to bulkiness of the bromine atom. So,further bromination is difficult.
Hence (a) is the correct answer.
answered Dec 5, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App