\[\begin {array} {1 1} (a)\;\sqrt {\frac{27}{7}(R-r)} & \quad (b)\;\sqrt{\frac{27}{5}g(R-r)} \\ (c)\;\sqrt {\frac{7}{5}g(R+r)} & \quad (d)\;\sqrt {\frac{17}{5}g(R-r} \end {array}\]

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

At the point $P, N=0$

$mg= \large\frac{mv^2p}{(R-v)}$

$V^2_p =(R-r) g$

$\large\frac{1}{2}$$mV_A^2 \bigg[1+ \large\frac{k^2}{R^2}\bigg]=\large\frac{1}{2} $$mV_p^2+mg2( R-r)$

$\qquad= \large\frac{1} {2}$$ m \bigg[1+\large\frac{k^2}{R^2}\bigg]$$V_p^2+2 mg (R-r)$

$\qquad= \large\frac{1}{2}$$m \bigg[1+\large\frac{2}{5}\bigg]$$ V_p^2+2mg (R-r)$

$\qquad= \large\frac{7}{10} $$m (R-r)g+2mg(R-v)$

$\frac{-1}{2}mV_A^2 \bigg[\frac{7}{5}\bigg]= \large\frac{27}{10}$$ m(R-r)g$

$V_A= \sqrt {\large\frac{27}{7} \normalsize (R-r)g}$

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...