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Total number of possible matrices of order $3\times 3$ with each entry 2 or 0 is

\[(A)\quad 9\quad(B)\quad 27\quad(C)\quad 81\quad(D)\quad 512\]

1 Answer

There are 9 entries in a $3\times 3$ matrix
 
each place can be filled with 2 or 0
 
9 places can be filled with $2^9=512$ way
 
Part (D) is the answer.

 

answered Mar 10, 2013 by sreemathi.v
 

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