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# Total number of possible matrices of order $3\times 3$ with each entry 2 or 0 is

$(A)\quad 9\quad(B)\quad 27\quad(C)\quad 81\quad(D)\quad 512$
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## 1 Answer

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There are 9 entries in a $3\times 3$ matrix

each place can be filled with 2 or 0

9 places can be filled with $2^9=512$ way

Part (D) is the answer.

answered Mar 10, 2013

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