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The number of $\pi-$bonds in ethane, ethene and ethyne are respectively

$\begin{array}{1 1}(a)\; 0,1,0&(b)\;0,1,2\\(c)\; 0,1,1&(d)\;0,2,3\end{array}$

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In ethane$(C_2H_6)$ there is no $\pi-$bond, all are sigma bonds only, in ethane $(C_2H_4)$ there is only one $\pi-$bond and in ethyne $(C_2H_2)$ there are two $\pi-$bonds.
Hence (b) is the correct answer.
answered Dec 6, 2013 by sreemathi.v
edited Apr 2, 2014 by sharmaaparna1

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