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Molecular orbital theory predicts the $F_2^{2+}$ ion has a bond order of

$\begin{array}{1 1}(a)\;0.5&(b)\;1\\(c)\;1.5&(d)\;2\end{array}$

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The bond order of $F_2^{2+}$ is two.
Hence (d) is the correct answer.
answered Dec 6, 2013 by sreemathi.v

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