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Q)

Which of the following molecule exhibits the largest bond angle?

$\begin{array}{1 1}(a)\;Angle\; F-B-F\; in\; BF_3&(b)\;Angle\; F-Be-F\; in\; BeF_2\\(c)\; Angle\; H-O-H \;in\; H_2O&(d)\; Angle\; Cl-C-Cl\; in\; CHCl_3\end{array}$

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A)
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Angle of F-Be-F in $BeF_2$ is the largest bond angle of the four, i.e., $180^{\large\circ}$.
Hence (b) is the correct answer.
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