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$BrO_3^-$ is isostructural with a noble gas species

$\begin{array}{1 1}(a)\;XeO_2&(b)\;XeF_4\\(c)\;XeO_3&(d)\; XeF_3\end{array}$

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$BrO_3^-$ is in trigonal pyramidal in shape. It is isostructural with $XeO_3$. In both cases, the central atom undergoes $sp_3^-$ hybridization.
Hence (c) is the correct answer.
answered Dec 6, 2013 by sreemathi.v

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