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The bond order of $[He_2]^{4-}$ is

$\begin{array}{1 1}(a)\;1&(b)\;0.5\\(c)\;1.5&(d)\;2.0\end{array}$

1 Answer

0.5
Hence (b) is the correct answer.
answered Dec 6, 2013 by sreemathi.v
 

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